Question

I am doing square roots.I have 3 x-20 square +9=36 how do I solve this symbolically?

Answer 1

can you draw it.. ? :(

Answer 2

not sure

Answer 3

\[3\sqrt{x-20}+9=36\]

Answer 4

\[i came up with 3\sqrt{x-7}\]

Answer 5

@nelsonc12 that looks perfect ;)...
\[\Large 3\sqrt{x-20}=36-9\]
\[\Large 3\sqrt{x-20}=27\] now divide by 3and you'll have
\[\Large \sqrt{x-20}=\frac{27}{3}\]
\[\Large \sqrt{x-20}=9\] now square both sides ...
\[\Large x-20=9^2 \]can you do it now ?

Answer 6

ok... hold on ;)

Answer 7

\[\LARGE x=9^2+20\]
\[\LARGE x=81+20\]
how about now ? :)

Answer 8

That's correct. Well done ;)

Answer 9

thank you do you know anything about f(x) to find domain and range

Answer 10

\[f(x)=\sqrt{?81-x^2}\]

Answer 11

post your questions on the wall not here... there should be someone to help if I'm not around...

Answer 12

okay thank youj

Answer 13

what do you have to find here?

Answer 14

\[\LARGE f(x)=\sqrt{81-x^2}\] do you mean this ?

Answer 15

hmm.. what is range now !! O_O ... let me go to google translate lol :$

Answer 16

well I'm not sure if I'm capable to do it, (I might be wrong something...) you better ask your question on the wall...
although I think
\[\LARGE f(x)=\sqrt{81-x^2}\]
\[\LARGE x\in [-9,9]\]
anyway to get sure post it on wall... Good luck !