Explain: log(x+3/10)+log x+1 =0
log(x+3/10)+log(x+1) =0 ??
^^yes
explain: use the log rule so you can rewrite the left side as the log of a quotient. since the bases are the same for the logs, the arguments are the same... solve...
log((x+3)/(x+1))
u good? i'm good... :)
looks like a typo there ** multiplication
log(x+3) - log(10) + log(x+1) = 0 log((x+3)*(x+1)) = log(10) (x+3)*(x+1) = 10
yep. @experimentX , is correct.... how did i miss that?
i'm not good
what have you been smokin buddy ... thats not like you!!
i've been at level 0 for several times today... :(
must be a bug.
log(x+3) - log(10) + log(x+1) = 0 log((x+3)*(x+1)) = log(10) (x+3)*(x+1) = 10 x^2 + 4x + 3 = 10 x^2 + 4x - 7 = 0 quadratic formula...
some maniac gave me ... i don't know how much medals ... i was at level 60 when i woke up i was at level 62. I messaged "why are you overdoing it?" I got reply ""[Hitler] has grasped the falsity of the hedonistic attitu ..... a result a whole nation flings itself at his feet." ...... -(George Orwell's review of Mein Kampf) Hopefully that will suffice."
a page long essay .. lol.
wow...
I am still confused at to which answer I should go with here.. (Forgive my beginnerness)
sorry... you'll need to solve that last quadratic equation: x^2 + 4x - 7 = 0. Since this is not factorable, you can use the quadratic formula.
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