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help please...Riemann sum: f(x) = 1/x on interval [1,6]; and n=5...
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\[\sum_{i=1}^{n} f(x i*) dx\]
ok n = 5 right?
so we divide the interval [1,6] into 5 parts we can use left hand endpoints or right hand endpiont so make life easy if we use left hand enpoints they are 1, 2, 3, 4, 5
WHY CANT WE USE TRAP!
so \[\sum_{k=1}^5 f(x_k)\Delta x =1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5} \]
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here since you are dividing the interval of length 5 into 5 parts, \(\Delta x=1\)
thank you
how about for 2x+1 (1,4) n=6
would it be 3 parts.. and dx = 1/2 ...i first plugged in f(1) = 2(1) +1 x 1/2...... but in order to get the right answer i must start at 1.5... i dont understand why
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