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lim (sqrt(x))(lnx) x->0
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that was wrong rewrite as \[\frac{\ln(x)}{\frac{1}{\sqrt{x}}}\] and use l'hopital
why is the limit as x->0 of lnx negative infinity?
do you know what the graph of \(y=\ln(x)\) looks like?
i guess the answer depends on the definition of \(\ln(x)\) if the definition is the inverse of the exponential function \(e^x\) then it is minus infinity since as x to so \(-\infty\), \(e^x\) goes to zero
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