Question

-5^3sqrt625 + ^3sqrt40

Answer 1

\[-5^{3}\sqrt{625}+3\sqrt{40}\]

Answer 2

,,radar" i think this ^3 wann to be cuberoot sign ...???

Answer 3

Is the -5 with an exponent of cube root of 625?

Answer 4

no there is cuberoot of 625 and cuberoot of 40 -- i think

Answer 5

\[-5^{\sqrt[3]{625}}?????\]

Answer 6

,,jmallis" -so how do you think ,please ?

Answer 7

,,jmallis" -so how do you think ,please ?

Answer 8

\[-5 \sqrt[3]{625}+\sqrt[3]{40}\]

Answer 9

right the second time with the 3

Answer 10

,,radar" exactly like ...

Answer 11

625=(5^3)*5
40=(2^3)*5

Answer 12

good luck

bye

Answer 13

\[-5(5)\sqrt[3]{5}+2\sqrt[3]{5}\]

Answer 14

\[-25\sqrt[3]{5}+2\sqrt[3]{5}=-23\sqrt[3]{5}\]

Answer 15

Not sure if this is the solution as I am not sure I have translated the problem. I have my doubts about the -5

Answer 16

@jhonyy9 do you think that is it? The -5 casts a doubt.

Answer 17

Anyway with what you have provided should be enough to finish it.

Answer 18

ok thanks