Question

I NEED HELP

a-2/a^2+5a+6 - 2a-3/3a^2+9a

Answer 1

is this subtracting two fractions?

Answer 2

yes

Answer 3

can you factor a^2 + 5a + 6 ?

Answer 4

yes

Answer 5

well factor the denominators...
and then put the fractions into common denominators

Answer 6

what did you get for a^2 + 5a + 6 ?

Answer 7

thats it... now the other one 3a^2 + 9a

Answer 8

so we have:
\[{a-2 \over (a+3)(a+2)} - {2a-3 \over 3(a+3)}\]
now what is the first denominator missing from the second one?