explain the concept of relative acceleration and relative displacement

Question

aravindg · Answer

is there sthng called relative time how is these useful in problem solving?

tetyana · Answer

Relative displacement and acceleration describes situations in which the velocities or positions of an object vary depending on the perspective. For instance, imagine you stand up in a flying airplane. The person next to you is sitting still (not accelerating), relative to you. However, a person looking from the ground up would say the person is moving at the same speed as the plane.

aravindg · Answer

wt do u say?

anonymous · Answer

First, there is something known as relative time. It's explained by Einstein in his work with special relativity. I'm not knowledgable enough to explain it. 

Second, relative displacement and acceleration are how two objects move relative to each other, as opposed to how things move in reference to the ground frame (which is fixed and attached to the surface of the earth). 

Let's give me an example. 

Let's say Bob and Jim are standing side by side. Bob walks 10 m forward, and Jim walks 5 m forward. Their relative displacement is 5 m because$$d_r = {d_b - d_j}$$

Again, Bob and Jim are standing side by side. Bob accelerated as 10 m/s^2 and Jim accelerates at 5 m/s^2. Their relative acceleration is 5 m/s^2$$a_r = a_b - a_j$$

anonymous · Answer

Difference

aravindg · Answer

hm u see ihad a qn where a two balls where thrown  simultaneously ,one from top of a tower and other frm below it was said by my teacher that we could get the time when they coolide by using relative velocity and relative displacement hw is that possible.explain @eashmore

anonymous · Answer

I didn't see the question. Post it here.

anonymous · Answer

relative acceleration... http://rrg.utk.edu/resources/ME231/lectures/ME231_lecture_13.pdf relative displacement... http://www.iitk.ac.in/nicee/wcee/article/11_1103.PDF

anonymous · Answer

time/relative time... http://en.wikipedia.org/wiki/Time_in_physics

aravindg · Answer

A stone is allowed to falll form from the top of a tower 100 m high.Another stone is projected vertically with a velocity 25 m/s at the same time .When and where will the 2 stones meet?

anonymous · Answer

For the stone falling downwards, distance = 0.5 * g * t^2 = 5t^2
Or, t^2 = 100/5 = 20 
Or, t = 2 root 5 seconds
So, it will fall in 2 root 5 seconds.

anonymous · Answer

both rocks will touch the ground at the same time...

anonymous · Answer

|dw:1334124476284:dw|