Solve x^2-3x-10=0 by completing the square.

Question

anonymous · Answer

(x-5)(x+2) = 0
x = 5, -2

anonymous · Answer

The answer is correct. Is that good enough for you?  Or do you want to see how it was done?

anonymous · Answer

Can I see how it was done?

anonymous · Answer

i pretty much did all the work
You could add this step: x^2 - 5x + 2x - 10 = 0

anonymous · Answer

and then the rest

anonymous · Answer

OK, give me a moment to write all the steps out.

anonymous · Answer

$$Ax ^{2}+Bx+C=0$$

First step take the B value and divide it by 2. So you have 3/2.

Second step square the value you found in step 1. So you have 9/4

Third step rewrite the equation. So you have $$x ^{2}-3x-9/4+9/4-10=0$$This will factor out to be $$(x-3/2)^{2}-9/4-10=0$$ This becomes

$$(x-3/2)^{2}-49/4$$ This becomes$$(x-3/2)^{2}=49/4$$Now that the square root of both sides.$$(x-3/2)=\pm7/2$$$$x=\pm7/2+3/2$$
x=-2 or x=5

anonymous · Answer

Thank you! :D

anonymous · Answer

When I wrote divide the B value is should be -3/2.  And it should say Now take the square root of both sides.