Question

f(x)= the square root of 6-x and g(x) = x+1

find (f+g)(15)

Answer 1

f+g or fog??

Answer 2

(f+g) ...

the answer choices are
a) 19
b)20
c)21
d)undefined

Answer 3

\[(f+g)(15)=f(15)+g(15)\] does not exist because
\[f(15)\] is not a real number

Answer 4

if it is undefined i would still like to know how to go about it though...
lost on where to start

Answer 5

@Arnab09 do you agree ?

Answer 6

replace x by 15

Answer 7

\[f(15)=\sqrt{6-15}=\sqrt{-9}\]which is not a real number

Answer 8

Thank you so much for explaining it !

Answer 9

yw