Question

Find 3 consecutive intergers such that the product of the smallest and the largest is one less than nine times the middle interger.

Answer 1

let the numbers be x-1, x, x+1
so according to qsn
(x-1)*(x+1)=9x-1
by solving it the numbers you get are 8,9, 10...

Answer 2

let the 3 consecutive numbers equal x, x+1 and x+2, respectively.
It follows (from the question) that (x)(x+2) = 9(x+1) - 1
therefore, \[x ^{2} -7x-8=0\]
therefore, x = 8 or -1

Answer 3

yeah -1, 0, 1 also satisfies the solution.. :)