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What would a parabola's points be for the equation: Y=x^2+4x+1 When the values start at -5?
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okay can by point you mean the vertex?
The vertex will be one of them...
and "values start at -5". that's for the domain?
I'm guessing so, that's all the instructions tell me.
okay.
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+|dw:1334173641851:dw| \ now vertex of a standard parabola ax^2 + bx +c is (-b/2a . -D/4a) where D is the discriminant \[D = \sqrt{b^2 - 4ac}\] compare the equation of your parabola with that of this std. parabola, get , b, c a=1 b=4 c=1 so plug the values, and get the vertex!
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