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The domain of the parabola x - 2 = -4(y - 3)^2 is
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is x > 2 right?
how would i even graph this on a calculater considering its (y-3)^2? i always get confused!
the coefficient on the y side is negative, so id go with x<2
oh yes good point! didnt notice that, do you know how i could isolate y in an equation lik ethis?
x-2 = -4(y-3)^2 (x-2)/-4 = (y-3)^2 \[\sqrt{(x-2)/-4} = y-3\] \[\sqrt{(x-2)/-4} +3 = y\]
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@wom u are a lifesaver!!! Thanks a bunch!
wombat* lol
Sure thing :) oh and the side with sqrt((x-2)/-4) +3 is going to have a + and - in front of it i think
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