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16 < 3x + 1 < 4 Part 1: Solve the inequality above. Part 2: Describe the graph
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that doesn't make since 16<4 is not true
sense*
how can x be both greater than 5 and less than 1?
i think answer is phi
@vegas14 there is no such x to make this inequality true...the answer is no solution
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or better to say not true
Oops
for any x
Well, I wouldn't go that far.
do we take intersections or union of sets while solving such inequalities?
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16 < 3x + 1 < 4 16 - 1 <3x < 4 - 1 15 < 3x < 3 15/3 < x < 3/3 5 < x < 1 false Therefore x < 1 or x > 5 |dw:1334203805217:dw|
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