Question

How to make this integral ∫dP/(P- P^2 ) thanks in advance!!!

Answer 1

\[\int\frac1{p(1-p)}dp = \int\frac{1}{p}dp + \int\frac{1}{1-p}dp = \ln p + \ln (1-p) +c\]

Answer 2

except the last term should be -ln(1-p)
u = 1-p
du = -dp
...

Answer 3

Oh yeah, thanks chris.

Answer 4

thank you so much!