Question

The legs of a right triangles measure (m − 3) in. and (n + 3) in. Which is the length of square of its hypotenuse?

Answer 1

please explain!

Answer 2

\[(m-3)^{2}+(n-3)^{2}\] pythagoras theorem buddy

Answer 3

\[(m-3)^2+(n+3)^2=h^2\]

Answer 4

yes but how do you simplify it?

Answer 5

answer choices :
m2 + n2 − 6(m − n) + 18
m2 + n2 + 6(m − n) + 18
m2 + n2 + 6(m − n) + 9
m2 + n2 − 6(m

Answer 6

square the each terms arrange the like terms together it's simple dude

Answer 7

When you finish this could you please help me wiyh mine

Answer 8

so m^2+n^2+(9+-9)? that doesnt get any of the answers

Answer 9

dude \[(-3)^{2}=(3)^{2}=9\]

Answer 10

oh -.-

Answer 11

wait what??

Answer 12

similarly \[(m+3)^{2}=m ^{2}+3^{2}+2*3*m\]

Answer 13

\[(m-3)^2+(n+3)^2=h^2\]
\[m^2-6m+9+n^2+6n+9\]