The legs of a right triangles measure (m − 3) in. and (n + 3) in. Which is the length of square of its hypotenuse?

Question

anonymous · Answer

please explain!

anonymous · Answer

$$(m-3)^{2}+(n-3)^{2}$$        pythagoras theorem buddy

anonymous · Answer

$$(m-3)^2+(n+3)^2=h^2$$

anonymous · Answer

yes but how do you simplify it?

anonymous · Answer

answer choices :
 m2 + n2 − 6(m − n) + 18 
   m2 + n2 + 6(m − n) + 18 
   m2 + n2 + 6(m − n) + 9 
   m2 + n2 − 6(m

anonymous · Answer

square the each terms arrange the like terms together it's simple dude

anonymous · Answer

When you finish this could you please help me wiyh mine

anonymous · Answer

so m^2+n^2+(9+-9)? that doesnt get any of the answers

anonymous · Answer

dude $$(-3)^{2}=(3)^{2}=9$$

anonymous · Answer

oh -.-

anonymous · Answer

wait what??

anonymous · Answer

similarly $$(m+3)^{2}=m ^{2}+3^{2}+2*3*m$$

anonymous · Answer

$$(m-3)^2+(n+3)^2=h^2$$
$$m^2-6m+9+n^2+6n+9$$