A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.

Question

A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.

rogue · Answer

It's a quadratic equation, so its min/max will be at $$x = \frac {-b}{2a}$$

rogue · Answer

Well, in this case,$$t = \frac {-b}{2a}$$After you solve for the t value, plug it into h(t) to get the max height.