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OpenStudy (anonymous):
Can you help me prove the following identity please?
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OpenStudy (anonymous):
OpenStudy (anonymous):
I think it would be easier to do LHS no?
OpenStudy (anonymous):
recall what sin^2(theta)=1/2(1-cos2(theta)), there is one similar to for cos^2(theta)
OpenStudy (anonymous):
Yes, thats the first pythagorean identity if im not wrong
OpenStudy (anonymous):
so for cos² theta, it would be 1-sin²theta
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OpenStudy (anonymous):
actually it the same as for sin^2(theta) except its +cos2(theta)
OpenStudy (anonymous):
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