Question

practice factoring is it right?
16 x^4 - 4y^2
(2x^2 + y) (x^2 -y)

Answer 1

if it is wrong dont give me answer point where i went wrong pls

Answer 2

You can simplify it first by taking out the common factor 4
4(4x^4-y^2)
Now we can factor more easily
4x^4-y^2.
4x^4 should be the product of the first term of the factors
It could be
(2x^2 + ) (2x^2 + )
or (4x^2 ) (x^2 + )
-y^2 should be the product of the second term of the factors
( -y) ( +y)
And the middle the term should be equal to 0 so it would be.
(2x^2-y) (2x^2+y)
So the answer is
4(2x^2-y)(2x^2+y)