Write an equation for a line perpendicular to and passing through the point (-6,2)
perpendicular to what?
perpendicular to y=-2x-2
perpendicular to \(y=-2x-2\) a line with slope \(-2\) will have slope \(\frac{1}{2}\)
your slope is \(\frac{1}{2}\) and your point is \((-6,2) \) use the point slope formula to find the equation of the line
\[y-y_1=m(x-x_1)\] with \(m=\frac{1}{2},x_1=-6,y_1=2\) \[y-2=\frac{1}{2}(x+6)\]
If an equation is in y = mx+b form, then the slope is m. The slope of a perpendicular has the opposite reciprocal as it's slope. That is, flip it and then make it negative.
\[y-2=\frac{1}{2}x+3\] \[y=\frac{1}{2}x+5\]
Thank you! I have another problem if you're willing to help!(:
It costs XYZ Corporation $7500 to produce 1400 units and $4440 to produce 500 units. Let C represent the cost in dollars and x represent the number of units produced. Find a linear equation for C in terms of x.
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