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need help on this problem that seems to stump a few people...
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\[A = a b \sin \theta\]\[17 = a \times 13 \times \sin \frac {\pi}{4}\]\[17 = 13 \frac {\sqrt 2}{2}a\]\[a = \frac {17 }{13} \sqrt 2\]
The pi/4 is 45 degrees in radians.
neither worked.
\[A=\frac12ab\sin\theta\]I think...
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oh, lol... Sorry.
It should be (34/13) sqrt 2 then.
haray. Rogue, thank you and nice job. I asked this numerous times and no one got it. thanks again.
yw, and thanks turing :)
welcome Rogue I just float around and nitpick ;)
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