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Mathematics 16 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Mrs. Beluga? What a horrible name.

OpenStudy (dumbcow):

not sure what middle ornate refers to? i know that distance is inversly proportional to speed do you have the formula or i can look it up

OpenStudy (dumbcow):

speed squared i should say *

OpenStudy (anonymous):

i have no idea, lol

OpenStudy (anonymous):

The formula is velocity = distance/time. I don't understand any of the terminology used in that question though.

OpenStudy (anonymous):

im so confused with this. aha.

OpenStudy (dumbcow):

here is a reference http://www.webs1.uidaho.edu/niatt_labmanual/Chapters/geometricdesign/theoryandconcepts/BrakingDistance.htm so the equation would look like this assuming the stopping distance is 52 ft 52 = v^2/2(32.2)(0.2) 52 = v^2 / 12.88 v^2 = 669.76 v = 25.88 ft/sec

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