Find the missing parts of the triangle. (Find angles to the nearest hundredth of a degree.)

a = 6.1 in.
b = 13.6 in.
c = 16.0 in.
Answer
a A = 21.92°, B = 56.34°, C = 101.74°
b A = 19.92°, B = 56.34°, C = 103.74°
c A = 23.92°, B = 54.34°, C = 101.74°
d No triangle satisfies the given conditions.

Question

Find the missing parts of the triangle. (Find angles to the nearest hundredth of a degree.)

a = 6.1 in.
b = 13.6 in.
c = 16.0 in.
Answer
	a	A = 21.92°, B = 56.34°, C = 101.74°
	b	A = 19.92°, B = 56.34°, C = 103.74°
	c	A = 23.92°, B = 54.34°, C = 101.74°
	d	No triangle satisfies the given conditions.

anonymous · Answer

well wait.. cant you use the answers for your own good?

alexwee123 · Answer

this time USE LAW OF COSINES

anonymous · Answer

wait nvm. it doesnt tell u an angle haha

anonymous · Answer

$$Cos \theta(C) =\frac{a^{2}+b^{2}-c^{2}}{2ab}$$

alexwee123 · Answer

there were so many trig questions today :o

anonymous · Answer

for angle B $$\cos \theta (B) =\frac{ a^{2}+c^{2}-b^{2}}{2ac}$$

anonymous · Answer

A is the answer, btw @helloimjared  u have to work this out

anonymous · Answer

You saying u want me to draw it on here and get the answer?