Two 104 kg lead spheres are suspended from 96-m-long massless cables. The tops of the cables have been carefully anchored exactly 1 m apart.
What is the distance between the centers of the spheres?
I came up with this equation, but it is apparently wrong.
104*10/(sin(arctan(96/x)))*cos(arctan(96/x))=6.67300E-11*104^2/(1-2x)^2
where 1-2x would be the answer to the question.
I got my equation setting the gravitational force between the two balls equal to the horizontal component of the tension in the string.

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