Co-geometry question #1
Sorry, my brain is not functioning well at the moment. Here's an extremely easy question
AB = 4/3 and AC =1 and the coordinates of B and C are given
seems like you can get x and y solving the distance equations http://www.wolframalpha.com/input/?i=solve+%28x%2B5%2F3%29%5E2+%2B+y%5E2+%3D+%284%2F3%29%5E2%3B+x%5E2%2By%5E2+%3D+1 slope will be quite easy.
Yup, this is one of the methods, but there is another way to do it, and my question is from there. It's using tan
must be some other special elegant method.
Indeed, a very cute solution :)
slope = tan (angle ABC) = 1/ (4/3) = 3/4
Now problem is how do you find that angle??
I understand how it comes. But not sure when does it work. When should I use tangent ratio?
the problem is I don't know when to use tan ratio to find slope and when I can't
Oo ... did i hear something like 3/4 is the answer??
No, but you saw :P
Lol ... I hadn't realized it yet. I'm quite thick headed, I never listen to anyone. I think you can take tan ratio as slope when your base is parallel to x-axis.
what do you mean by 'base' ?
|dw:1334303309981:dw| If \(\theta\) is the reference angle, then b is base, if this b is parallel to x-axis then we can take tan theta as slope.
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