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Mathematics 7 Online
OpenStudy (anonymous):

Mike wants to rent a car for his vacation. The rental costs $130 a week plus $0.20 a mile. How far to the nearest mile can Mike travel if he wants to spend $325 at most?

OpenStudy (anonymous):

Discount the rental cost from the total cost. What do you get?

OpenStudy (anonymous):

There is also the question of how man weeks does this person rent the car for?

OpenStudy (anonymous):

To maximize the miles driven, we want to minimize the fixed costs, the weekly rate. So, let's assume he kept the car for only one week, thereby incuring $130 in rental fees. This leaves $325-$130=$195 for mileage. At $0.20/mile, we have $195/($0.20/mile)=975 miles.

OpenStudy (anonymous):

Dont assume because then you make an A*SS out of U and ME

OpenStudy (anonymous):

Ok.. Let us "assert" that he rented the car for one week. He cannot very well rent the car for zero weeks, and if he rented the car for more than one week, he would have less money left to spend on mileage.

OpenStudy (anonymous):

Let x = total miles driven then .20x+130=325 .20x=195 x=975 miles

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