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convert to polar form x=2
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same formula as I showed you in the last question did you not understand it?
not really, I was sick when my class went over this so I have no idea what I'm doing
look at your other post I just responded to
So for polar form, we will give the position as (r, theta). Since x=2 is a vertical line, we get the radius varying with theta.
|dw:1334340761477:dw|It looks to me that r=2sec(theta)
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So your answer in polar form is \[(2\sec \theta,\theta)~~-\frac{\pi}{2}<\theta<\frac{\pi}{2}\]
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