In an experiment to determine the rate at which heat is extracted from a hot material, 317g of the material at 90°C is put into a 50mm diameter copper vessel to a depth of 90 mm as shown below. The hot material and calorimeter are placed in a container holding 221g of cold water at 22.7°C. The temperature of the water is then measured every 30secs for 3mins.The results are plotted as in the previous question and the average temperature rise per second is calculated as 0.0065 ±0.0005°C/sec.
From the data provided and the graph below, determine the average heat power(kW) transferred to the wate

Question

In an experiment to determine the rate at which heat is extracted from a hot material, 317g of the material at 90°C is put into a 50mm diameter copper vessel to a depth of 90 mm as shown below. The hot material and calorimeter are placed in a container holding 221g of cold water at 22.7°C. The temperature of the water is then measured every 30secs for 3mins.The results are plotted as in the previous question and the average temperature rise per second is calculated as 0.0065 ±0.0005°C/sec.
From the data provided and the graph below, determine the average heat power(kW) transferred to the wate

anonymous · Answer

attachment

anonymous · Answer

Pcond=kA(Th-Tc)/L (is this the forumla and do you have to do something else....i'm always getting it wrong)

experimentx · Answer

Pcond=kA(Th-Tc)/L what are these??

anonymous · Answer

p=power
k= material constant
a=area
Th=temperature hot
Tc=temperature cold
L=length

anonymous · Answer

thats all exptx has given u the power eqn u need to use taht