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-4^-2
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-1/4^2=?
If we have something this we always consider, -(4)^-2 Same as we get sometimes, x+2/x It means, \[x + \frac 2x\]
\[a^{-n} = \frac 1 {a^n}\]
@vi3tbloodxx that's wrong. :l
did i understand the question wrong?
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No, I didnt i guess.
that is the answer for, (-4)^(-2) = 1/(-4)^2 = 1/16 Whereas, -4^-2 = -1/4^2 = -1/16
@apoorvk you are correct.
What's the difference between -4^-2 and -(4^-2) and (-4)^(-2) ?
\[\Large -4^{-2} = -(4^{-2}) = -\frac{1}{(-4)^2} = -\frac{1}{16}\] -(4^-2) same as above \[\Large (-4)^{-2} \to (\frac{1}{4})^2 = \frac{1}{16}\]
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Thank you very much. I really appreciate your help and everybody else's contribution is appreciated. Keep up the excellent work you're doing.
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