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Differentiate f(x) = x^x
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f(x)' =x(x)^x-1
how did u get that eyad?
f(x) = x^x Let f(x) = y y = x^x lny = x*lnx Then take derivative of both side: y'/y = lnx + 1 y' = y(lnx+1) Substitute y back in from original equation: y' = x^x(lnx+1)
@ryman : its a law ,, if u got an (x) powered with a number , then its derivative = let the number get down next to the x ,and subtract from the power one . :)
You can't use the power rule in this case. You have to solve it by implicit differentiation.
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but the power is not a number its a variable
|dw:1334354214316:dw| multiply both sides by y (or x^x) to get y'
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