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Mathematics 14 Online
OpenStudy (anonymous):

Can anyone help me?

OpenStudy (dcolley):

with what?

OpenStudy (anonymous):

That one

OpenStudy (dcolley):

we just started learning this

OpenStudy (anonymous):

I'm having troubles with it. I know b<0, but not a

OpenStudy (anonymous):

Oh ,, I posted the wrong question

OpenStudy (anonymous):

There you are~

OpenStudy (anonymous):

Though, the previous one is also the question I don't know. Just do it later.

OpenStudy (anonymous):

if x was zero then b would be........

OpenStudy (anonymous):

I told you I know b<0. I don't know range of value for a only

OpenStudy (anonymous):

a has to be postive

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

we know b is negative ... x is postive /...... x^2 is postive ......-x^2 is negative... so we have two negative terms but still ax is reaching above the x axis... we x is postive ..... so a must be postive to make ax postive plus ax has to be greater than -x^2+b

OpenStudy (anonymous):

OMG, I've never though in that way. Thank you!

OpenStudy (anonymous):

cool but b could be so large like -1000000 that it would never go above the line

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