Question

evaluate. this

Answer 1

lim(x--> 0) (e^x - e^-x / e^x +e^-x)

Answer 2

I'd say zero. The numerator goes to zero, and the denominator goes to two. What is there that you didn't understand about the problem?

Answer 3

answer is e^2 -1/ e^2 +1, and I dont understand this answer how did it come

Answer 4

seems zero
http://www.wolframalpha.com/input/?i=lim+x-%3E0+tanhx

Answer 5

Is it:\[\lim_{x \rightarrow 0} (e^{x} - e^{-x})/(e^{x} + e^{-x})\]If so, the limit is 0

Answer 6

http://www.wolframalpha.com/input/?i=lim+x-%3E0++%28e%5Ex+-+e%5E-x%29+%2F+%28e%5Ex+%2Be%5E-x%29+

Answer 7

its , rediculous, how the answer given is different frm 0 , I also cme to a conclusion in he begning that the lvalue is 0