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Mathematics 19 Online
OpenStudy (karatechopper):

im so confused on this problem i have no clue where to star

OpenStudy (karatechopper):

http://www.glencoe.com/sites/common_assets/support_pages/a1_OK_eoi_se.pdf if u go to link above then u type in to go to page 37/59 u will see a page pop up..i need help with number 1

OpenStudy (karatechopper):

he colleced 250 winning tickets, i know tht for sure

hero (hero):

Which still means nothing in terms of getting a free meal.

OpenStudy (lgbasallote):

ahhh teachers and their senseless questions lol

OpenStudy (karatechopper):

does anyone understand this problem!?!?!?

OpenStudy (karatechopper):

idk i just need to figure it out its so hard..

OpenStudy (karatechopper):

my dad just looked at it and can solve it..he wont tell me how to solve it tho!

OpenStudy (karatechopper):

thank u

hero (hero):

75

hero (hero):

Still the strangest problem I've ever seen

OpenStudy (karatechopper):

lets see what ash has to say

OpenStudy (ash2326):

From the frequency table for free family meal= there were 450 tickets Now if we have a ticket, then probability of it getting us a family meal is \[\frac{450}{1500}\] Mike collected 250 so he can expect \[250 \times \frac{450}{1500}= 75\ family\ meals\]

OpenStudy (karatechopper):

ha! just before u posted tht my dd said the same thing!

OpenStudy (ash2326):

wow:)

hero (hero):

Well, I must have posted the answer before your dad said anything

hero (hero):

I solved it by setting up a proportion: \[\frac{450}{1500} = \frac{x}{250}\] x = no of expected free meals

OpenStudy (karatechopper):

lol u posted it after...can u help me on a easier question? itsdifferent than this

OpenStudy (karatechopper):

type in page 38/59 and look at question 3

OpenStudy (ash2326):

Alvin is hitting on the board every time. He can hit any part of the board. All the case have equal probability so We need to find the probability of hitting outside the circle. Let's first find the area of that portion Area of square Side of square= \(2 \times 12\)=24 inches So Area= 576 inches^2 Area of circle= \(\pi \times r^2\) r= 12 inches so Area of circle=\( 3.14 \times 12^2\)=452.16 inches ^2 Area outside of the circle= 576-452.16=123.84 inches^2 Probability of hitting this area \[\frac{123.84}{576}= 0.215\] so it's 0.22

hero (hero):

Other than your dad @KC, I was the first to post the answer to the first question.

hero (hero):

What the.... there's an @KC ?

OpenStudy (karatechopper):

i didnt want the answer hero, i wanted how to solve it...to me ash was the first other than my dad:P i never ask for answers

OpenStudy (karatechopper):

everyone knows tht from my lectured to peepl

hero (hero):

Whatever. I posted the answer, then I showed you how I got it. Either way, I posted an answer first. Your dad isn't on Open Study and there's a chance that ash my have deducted from the answer that I posted what the steps were so I win :P

hero (hero):

On top of that, I posted an approach to the answer, which I believe is much simpler than ash's or your dad's steps. You should be more appreciative.

OpenStudy (karatechopper):

it doesnt matter im glad peepl help me..no winning or loosing:/

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