Question

Write the slope-intercept equation for the line that passes through (-8, -11) and is perpendicular to -2x – 7y = -14 Please show all of your work.

Answer 1

First find the slope of -2x-7y=-14 (change it into the form y=mx+b)
-7y=2x+14
y=-2/7x-2

So the slope of this line is -2/7
BUT
this line is perpendicular to the line being ask so we take its negative reciprocal to find the slope of the line we are looking form
7/2

Now we will use 7/2 and (-8,-11) to find the line using the point slope equation

y-y1= m (x-x1) where
y1=-11
x1=-8
m=7/2

So

y+11=7/2(x+8)
y+11= 7/2x +28
y=(7/2)x +28-11
y=(7/2)x +17 <---slope intercept form

Answer 2

Thank you