Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

x^2 + 24x + 90 = 0 how would i solve for x?

OpenStudy (anonymous):

With the quadratic formula.

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

its ax^2 + bx + c right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so how would i solve it though? thats the only part im stuck on

OpenStudy (anonymous):

the quadratic formula is \[(-b \pm \sqrt{b^2 -4ac}) / 2a\] with the variables you mentioned above plugged in, so -24 \[(-24 \pm \sqrt{24^2 -4(1)(90)}) / 2\]

OpenStudy (anonymous):

and setting it up this way will solve for x?

OpenStudy (anonymous):

yes. factoring is faster if possible, though. here it's not.

OpenStudy (anonymous):

oh ok ok now i would have to simplify the square roots too?

OpenStudy (anonymous):

yeah, you'd figure out the value of the radical/square root, then add/subtract it to/from -b and divide by 2a to get the answers

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!