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x^2 + 24x + 90 = 0 how would i solve for x?
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With the quadratic formula.
yeah
its ax^2 + bx + c right?
yes
so how would i solve it though? thats the only part im stuck on
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the quadratic formula is \[(-b \pm \sqrt{b^2 -4ac}) / 2a\] with the variables you mentioned above plugged in, so -24 \[(-24 \pm \sqrt{24^2 -4(1)(90)}) / 2\]
and setting it up this way will solve for x?
yes. factoring is faster if possible, though. here it's not.
oh ok ok now i would have to simplify the square roots too?
yeah, you'd figure out the value of the radical/square root, then add/subtract it to/from -b and divide by 2a to get the answers
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