Question

please help and tell me steps too

Answer 1

lim x->a {x^2 - (a+1)x +a^2) / (x^2 -a^2)}

Answer 2

wow SO MANY VIEWERS...goood good

Answer 3

not by expasion please.....

Answer 4

what about l'hopital's rule

\[\lim_{x \rightarrow a} f(x)/g(x) \]

anf g'(x) exists then

\[\lim_{x \rightarrow a} f'(x)/g'(x)\]

differentiate numerator and denominator

f'(x) = 2x - a - 1
g'(x) = 2x

\[\lim_{x \rightarrow a} (2x - a - 1)/2x\]

you can finish it from here

Answer 5

L'Hopitals Rule only applies if you get something like:\[\frac{0}{0},\frac{\infty}{\infty}\]if you plug in a, the denominator becomes 0, but the numerator doesnt, only for certain values of a. We cant use L'Hopitals since we dont know what a is.

Answer 6

an please tell me that where Im wrong in this question
lim x->0{ ( 1-cos3x)/(x^2)}
answer is 9/2 but mine is 9/4