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factorise 3(x+2)^2-10(x+2)+3 help me pleasee :)
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simply take (x+2) as A
then you will get a quadratic in A which you can easily solve,i presume???
Assume (x+2) = t. then solve for t then substitute t=x+2 and get x!!
or if you prefer the longer method, open brackets the whole term to a new quadratic in 'x'. then factorise. But the former was a cleverer method.
3A^2- 10 A +3 3A^2 - 9 A -A +3 3A(A-3) - 1(A-3) (3A-1)(A-3) substitute the value of A and PRESTO!!!! you have got your value of X
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PRESTOOOO!!!! ALAKAZAAAM!!!
LOL
thanks guys! :)
First expand to get \[3 x^2+2 x-5 \] Then factor \[ (x-1) (3 x+5) \]
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