Question

The length of a rectangular garden is 8ft more than twice its width. The area of the garden is 64 sq ft. Find the length and width of the garden. Please explain solving process.

Answer 1

let x be the width
the length is 8ft more than the width...how would you express this?

Answer 2

(x+8) (x) = 64

Answer 3

right :D now how do you solve for x?

Answer 4

x^2+8x+64

Answer 5

Hmm there's something wrong...you transposed 64 to the left side meaning its sign changes...can you do it again?

Answer 6

-64

Answer 7

yes now equate our equation to 0

Answer 8

Do you need help?

Answer 9

i am trying to find multiples of 64 that add 8x

Answer 10

8x+x^2-64 = (x )(x )

Answer 11

ok we made a huge mistake....the length is 8 more than twice the width :))

Answer 12

(x) (2x+8) = 64
2x^2+8x=64
2x^2+8x-64
x^2+4x-32=0
there

Answer 13

k

Answer 14

i leave the rest to you then

Answer 15

im stuck at (x+8) (x-4)

Answer 16

equate those factors to 0. what of those two could be a possible measure of anything?

Answer 17

-8 and +4?

Answer 18

yeah so from those two which one can be a measurement?

Answer 19

8*4=32

Answer 20

umm that's not what i meant...is there such thing a -8cm?

Answer 21

no

Answer 22

ohh I forgot the 2x (-8 +4)

Answer 23

so 4 would be the length of?

Answer 24

2x (-8+4) that's still not it

Answer 25

width

Answer 26

yes and the length would be ?

Answer 27

64/4=16

Answer 28

correct :D

Answer 29

Length = 16 Width = 4