Question

I have function z=(sin(x^2+y^2))^1/2 i have to define domain of x

Answer 1

There is no restriction on the x variable.\[x \epsilon \mathbb{R}\]

Answer 2

how did u solve it? sin variates between 1 and -1 but what its inside the square root must be major than zero

Answer 3

True, what is inside the square root must be greater than or equal to zero. Since we are dealing with x^2 inside the square root we will always get a positive value (or zero) regardless of the value x takes. x can be any real number in this function.

Answer 4

x^2+y^2 must be between 2k*pi and (2k+1)*pi for some k