Question

Check my integration for problem. Wolfram alpha is giving me a different answer than my calculations.

Answer 1

My work:



sinxcos^2x U= cos, du = -sin

sinxu^2


-int u^2 du ----> (pi/2)(0)-S u^3/3

(pi/2)S(0) -cos^3/3

-(1/3)cos^3(pi/2) - -(1/3)cos^3(0)

1/3

Answer 2

@ishaan94 @mertsj

Answer 3

sin is the derivative of cos sooo

\[-\frac{1}{3}cos^3(x);[0,pi/2]\]

pi/2 goes zero

0 goes 1

\[\frac{1}{3}\]

Answer 4

http://www.wolframalpha.com/input/?i=integrate+sin%28x%29cos%5E2%28x%29+from+0+to+pi%2F2

wolf is the same

Answer 5

d'oh! Looks like I plugged in the wrong equation! Thanks!