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Mathematics 17 Online
OpenStudy (anonymous):

I need help, but please try not to give me the answer: it says let v1=(3,5) and v2=(-4,7) compute |v1| and |v2|

OpenStudy (slaaibak):

|v1| = distance of the vector v1. Do you know the formula?

OpenStudy (anonymous):

No, not really.

OpenStudy (slaaibak):

if v = (a,b) |v| = sqrt(a^2 + b^2)

OpenStudy (anonymous):

Okay, but what about |v2| |V1|= sqrt(3^2+5^2)=5.83 |v2|=sqrt(-4^2+7^2)=8.06 Am I right?

OpenStudy (roadjester):

It's basically the pythagorean theorem. This is leaning a bit more towards physics (for me) but I think the notation is similar in a sense.

OpenStudy (roadjester):

I get the same answer but I'm not sure If the methodology is the same.

OpenStudy (anonymous):

Okay thanks

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