Question

Perform the modular arithmetic operation. [(11 ∙ 4. + 6] (mod 8)
A. 1

B. 5

C. 3

D. 2

Answer 1

You can either do the arithmetic like normal, then reduce your answer mod 8, or reduce everything mod 8, then do the arithmetic. It doesnt matter.

Answer 2

11 x 4 + 6 = 50

50/ 8 = 6 remainder 2

so its mod 2

Answer 3

So you could do 11*4+6=50, and 50 mod 8 is 2, or reduce 11 mod 8, which is 3, times 3 is 12, reduced mod 8 is 4, plus 6 is 10, reduced mod 8 is 2.

Answer 4

times 4, not 3, my bad.

Answer 5

maybe it is \(\equiv 2(\text{ mod 8})\)