Question

LAST ONE! Find an equation of a line tangent to a circle x^2+y^2=10 at (-1. 3).

Answer 1

\[2x+2yy'=0\]
\[y'=-\frac{x}{y}\] plug in your point to get the slope

Answer 2

\[y'=-\frac{-1}{3}=\frac{1}{3}\] is the slope, if you need the equation use the point slope formula

Answer 3

y= 3x+10/3 ???

Answer 4

or do i keep the 1/3 ? and make it y=1/3 x +10/3 ??

Answer 5

\[y-y_1=m(x-x_1)\] with
\[m=\frac{1}{3},x_1=-1,y_1=3\]