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Mathematics 7 Online
OpenStudy (anonymous):

how do I graph a conic?

OpenStudy (anonymous):

you'll need the equation of the conic in standard form first... do you have an equation?

OpenStudy (anonymous):

Yes! (x+6)^2/25 + (y-2)^2 =1 I do believe this is an ellipse

OpenStudy (anonymous):

yes it is an ellipse... (x-h)^2/a^2 + (y-k)^2/b^2 = 1 is the standard form for an ellipse where (h, k) is the center and 2a is your major axis 2b is your minor axis...

OpenStudy (anonymous):

let's start what's your center?

OpenStudy (anonymous):

would it be (-6, 2)?

OpenStudy (anonymous):

good. what's a and b?

OpenStudy (anonymous):

a is 2 b is -6

OpenStudy (anonymous):

a comes from the denominator under the x^2 term. since a^2 is 25 that means a = 5... you follow?

OpenStudy (anonymous):

yes! so that means that b is 10?

OpenStudy (anonymous):

is there a denominator under the y^2 term?

OpenStudy (anonymous):

100

OpenStudy (anonymous):

isn't it 1 ?

OpenStudy (anonymous):

how? I thought it would be the square root of 100, making it 10?

OpenStudy (anonymous):

|dw:1334566384435:dw| this is what you typed in right?

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