@Callisto
Ok. I will post question by question ok?
sure
How do I find the range of this?
The largest value - the lowest value
= 32.6 - 16.5
So the Range = 16.1?
Yup~ remember to add a unit :)
Oh so like 16.1degree?
degree Celsius
Right
Mean = sum of data / no. of data
Oh, so I add all of the values and then divide by 12 right?
Yes
Ok, so for b its 25.35 right>?
25.36, if you round the answer
ok
This function cannot be sinusoidal right?
I'm not sure. Perhaps we need to graph it?
Ok, I assume we will use the stat edit option from the t183
if we inpuit all the motnhly degrees in the x values in L1, what do we put as h values in L2?
I think it is not a sinusoidal...
How do I do C?
As the data goes up to reach the max. Then goes down to the position near to the starting position, it does not give a sine-like graph
Can this be considered as sinusoidal? http://www.wolframalpha.com/input/?i=plot+ [16.5%2C18.3%2C+21.8%2C+25.6%2C+29.2%2C+31.9%2C+32.6%2C+32.4%2C+30.3%2C+26.4%2C+21.3%2C+18.0]
sinusoidal : |dw:1334572790496:dw|
It is not sinusodial then, because while making a curve, it doesnt go negative and back up positive and create a pattern right?
Probably
Ok. Do you know how to use the stat menu in your calculator?
Why?
Because I think we are going to need to use this to solve problem e
My calculator is not that advanced :(
Add callisto, when I created a pattern while plotting in the graph, it created a sinusoidal right? It kind of looks like that http://www.wolframalpha.com/input/?i=plot+%5B16.5%2C18.3%2C+21.8%2C+25.6%2C+29.2%2C+31.9%2C+32.6%2C+32.4%2C+30.3%2C+26.4%2C+21.3%2C+18.0%2C16.5%2C18.3%2C+21.8%2C+25.6%2C+29.2%2C+31.9%2C+32.6%2C+32.4%2C+30.3%2C+26.4%2C+21.3%2C+18.0%5D
o.o Then it looks like a sinusoidal function. Sorry, then I made a mistake....
Its ok:) How do we determine the abcd?
I just found out that experimentX is helping you. You'd better follow his ideas. He's really smart and great while I'm not
I try asking in 2 different places because he is not 100% sure and I want to ensure I am going the right path
I'm doing the checking :)
ok. So i think the equation would be t = 23 [12x+4] + 32 Am I correct?
23 -> 8.05 still have to check the others
Its not 23? how come its 8?
a is the enlargement of the amplitude right?
yes
enlargement = (range)/2
ohh. okk
Somthing other than the value of a is wrong. im not getting the same graph
Are you offline?
This doesn't look good http://www.wolframalpha.com/input/?i=y+%3D+8.05+%5B%28sin%28x-48%29%2F12%5D+%2B+17.5
I'm sorry.. I needed some time to work out the graph..
Sure:) Thank you btw
This look prettier, but I think that's not the answer :S http://www.wolframalpha.com/input/?i=y+%3D+8.05+%5B%28sin%28x%2B36%29%2F12%5D+%2B+17.5
Yeah, I think it has to look an dbe placed somewhere along here: http://www.wolframalpha.com/input/?i=plot+ [16.5%2C18.3%2C+21.8%2C+25.6%2C+29.2%2C+31.9%2C+32.6%2C+32.4%2C+30.3%2C+26.4%2C+21.3%2C+18.0%2C16.5%2C18.3%2C+21.8%2C+25.6%2C+29.2%2C+31.9%2C+32.6%2C+32.4%2C+30.3%2C+26.4%2C+21.3%2C+18.0]
But that would be something like... quadratic...
OMG! this is killing me!
Could it be this? http://www.wolframalpha.com/input/?i=t+%3D+%2832.4-16.5%29%2F2+sin%282pi%2F12+x%2B48%29+%2B+%2832.4%2B16.5%29%2F2
experimentX 's one looks good to me... I've never imagined that this topic could be that difficult :S
I cant believe its this difficult in problem e of question 1:(
There are still 6 questions left, and each one is so long
are the values are a= 8 b =0.52 c = 48 d = 40
when i learnt this, i never need to learn this type of application problem.. :(
d = 24.5?
Oh your right:)
Do you think thats correct?
a=8.05 would be better, I think
http://www.wolframalpha.com/input/?i=t+%3D+8.05+sin%280.52+x%2B48%29+%2B+24.5
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