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Mathematics 7 Online
OpenStudy (anonymous):

@experimentX

OpenStudy (anonymous):

@experimentX can you help?

OpenStudy (anonymous):

I have already done problem a and b

OpenStudy (anonymous):

For c, Is it sinusoidal?

OpenStudy (experimentx):

16 - 32.6

OpenStudy (anonymous):

what?

OpenStudy (experimentx):

i don't think its sinsoidal.

OpenStudy (anonymous):

Ive already determined a and b

OpenStudy (anonymous):

a = 16.1

OpenStudy (anonymous):

b = 25.36

OpenStudy (experimentx):

can you put that data into array.

OpenStudy (anonymous):

Im not sure how to do that

OpenStudy (experimentx):

[16.5, ... ]

OpenStudy (anonymous):

oh, ok 16.5,18.3, 21.8, 25.6, 29.2, 31.9, 32.6, 32.4, 30.3, 26.4, 21.3, 18.0

OpenStudy (experimentx):

looks sinusoidal http://www.wolframalpha.com/input/?i=plot+%5B16.5%2C18.3%2C+21.8%2C+25.6%2C+29.2%2C+31.9%2C+32.6%2C+32.4%2C+30.3%2C+26.4%2C+21.3%2C+18.0%5D but not exactly. I guess it can be called sinusoidal.

OpenStudy (anonymous):

Ok, I think so too. you know about the stat menu in the calculator right?

OpenStudy (experimentx):

No ...

OpenStudy (anonymous):

This graph is not sinusoidal right? because while making a curve, it doesnt go negative and back up positive and create a pattern

OpenStudy (anonymous):

It does look like it

OpenStudy (anonymous):

How do I determine the values of abcd in this question?

OpenStudy (experimentx):

you should be able to determinate that .. measure vertical shift, horizontal shift,, period ... etc.

OpenStudy (experimentx):

you period is 12 half of the 16.5 and 32.2 ... smallest and greatest must be your vertical shift. Don't ask me horizontal shift.

OpenStudy (experimentx):

(16.5 + 32.2)/2 <--- vertical shift (32.2 - 16.5)/2 <--- horizontal shift.

OpenStudy (anonymous):

Omg, Thank you so much experimentx, You make it so easy to understand:)

OpenStudy (experimentx):

(32.2 - 16.5)/2 <--- **amplitude

OpenStudy (experimentx):

horizontal shift must be around +4 (left)

OpenStudy (anonymous):

OK, I will try to construct an equation

OpenStudy (experimentx):

don't be so much confident about my data. try double check.

OpenStudy (anonymous):

ok. So i think the equation would be t = 23 [12x+4] + 32 Am I correct?

OpenStudy (experimentx):

try graphing and compare.

OpenStudy (anonymous):

Something is wrong, im not getting the same graph

OpenStudy (anonymous):

Is yours 100% correct?

OpenStudy (anonymous):

I need to know so that I can determine abcd

OpenStudy (experimentx):

I am not sure .. looks pretty much the same.

OpenStudy (anonymous):

Ok. Thats the closest i will ever get, so does that mean that the values are a= 8 b =0.52 c = 48 d = 40

OpenStudy (anonymous):

d=24.5

OpenStudy (experimentx):

can you put it in wolframalpha??

OpenStudy (experimentx):

seems similar.

OpenStudy (anonymous):

@experimentX , how do I solve problem e?

OpenStudy (experimentx):

how would i know??

OpenStudy (anonymous):

Thank you for your help

OpenStudy (experimentx):

you are welcome :)

OpenStudy (callisto):

wow~~~ @experimentX is so nice to you @Open2study

OpenStudy (experimentx):

I think i misread your above statement as "How did i solve the problem?". Your equations seems fine to me. I'm gonna be offline for a while @Callisto please continue.

OpenStudy (anonymous):

I know:) he is

OpenStudy (experimentx):

see you guys later.

OpenStudy (anonymous):

Thanks again:) Bye

OpenStudy (experimentx):

Bye

OpenStudy (callisto):

BYE!!~~ Be Back Soon!! lol

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