Question

Solve the equation
3y(y+4)=15

Answer 1

Divide thru by 3 getting: y(y+4)=5
y^2+4y-5=0 factor
(y+5)(y-1)= 0 solve
y=1
y=-5

Answer 2

first of all multiply the 3y to the brackets so it will be
3y*y=3y^2 ,3y*4=12y
and then enter the 15 in the other side : it will be 3y^2+12y-15
and then u can take 3 common : 3 (y^2+4y-5) and then facorize :
3 (y-1) (y+5)