Question

If pq=3x, sq=5x-8, and os=x+1, find
a.pq
b.sq
c.os
d.oq

* i will draw the shape

Answer 1

PA and SQ are tangents to the circle?

Answer 2

PQ = SQ so you can solve for x: 3x= 5x-8

Answer 3

@dpaInc presumably. I giving him the benefit of the doubt.

Answer 4

***PQ

Answer 5

The only "tricky" part is knowing that the tangent and radius form a right angle, so you can use pythagoras to find QO, then subtract the radius OP to get QR

Answer 6

pq = sq tangents from an external point are equal

then pq = sq

3x = 5x - 8

8 = 2x

x = 4

pq = 12, sq = 12

Answer 7

os = 4 + 1 = 5

Answer 8

and to find oq use pythagoras' theorem the tangent and radius intersect at right angles...

so \[oq^2 = 12^2 + 5^2\]

oq = 13

Answer 9

thank you guys.