Question

The path of a ball in flight is p(x)=-0.23(x-3.4)^2+4.2, where x is the horizontal distance in meters and p(x) is the vertical height in meters. What is p(2)?

Answer 1

real equal real, imaginary equal imaginary
\[3-x=2\]
\[-2-y=-3\]

Answer 2

(3-2i)-(x+yi) = 2-3i


3-2i-x-yi = 2-3i


3-x-2i-yi = 2-3i


(3-x)+(-2i-yi) = 2-3i


(3-x)+(-2-y)i = 2-3i


Now equate the real parts to get

3-x = 2

-x = 2-3

-x = -1

x = 1


and equate the imaginary parts to get


(-2-y)i = -3i

-2-y = -3

-y = -3+2

-y = -1

y = 1