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Mathematics 25 Online
OpenStudy (anonymous):

derivative of cos(4x)

OpenStudy (anonymous):

and what is the value of the derivative at x=pi/4

OpenStudy (anonymous):

The derivative of cos is -sin. It's just something to remember. Therefore, the derivative of cos4x is -sin(4x). Just plug in pi/4 for the answer. Tell me what you got and we'll compare answers.

OpenStudy (anonymous):

i got 0

OpenStudy (anonymous):

btw isnt the derivative -4sin4x

OpenStudy (anonymous):

Ah! Sorry about that, I had a typo.

OpenStudy (anonymous):

I got 0 as well.

OpenStudy (anonymous):

okay, can u take me thru the steps of this question:

OpenStudy (anonymous):

|dw:1334618741182:dw|

OpenStudy (anonymous):

have to find derivative of that.

OpenStudy (anonymous):

its okay, i got it

OpenStudy (anonymous):

Outer function:sin^2 inner function: sqrt t D sin^2 * sqrt t * D sqrt t sin(2x) * sqrt t * (1/2)sqrt t sin(2x) * t/2 (t/2)sin(2x)

OpenStudy (anonymous):

is the derivative of 2cosx, -2sinx?

OpenStudy (anonymous):

Yep!

OpenStudy (anonymous):

um, y=sinx - cosx

OpenStudy (anonymous):

is the derivative cosx+sinx?

OpenStudy (anonymous):

yes

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