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Graph the equation using the slope and y-intercept. x+y=0
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try to consider y= mx+b
Im not sure if the slope would be 1 and the y-intercept would be 0? :/
y int is correct, but the slope isn't. try again
I dont know then. My teacher said if there was just x it had an imaginary 1 in front of it. :P
yes that's true, but your equation isn't in terms of y = what do you have to do to x?
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to solve for y-intercept substitute the value of x to 0 and solve for y eg// x+y=0 0+y=0 y=0 y- intercept is 0
Ok I have the y-intercept down, but Im confused with how to get the slope
x+y=0 y= -x+ 0 from the slope-intercept equation y=mx+b m stands for slope
so your slope would be?
-1?
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yes, right. Go graph it now :D
Okay thanks :D
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